#P1937A. Shuffle Party

Shuffle Party

No submission language available for this problem.

Description

You are given an array a1,a2,,ana_1, a_2, \ldots, a_n. Initially, ai=ia_i=i for each 1in1 \le i \le n.

The operation swap(k)\texttt{swap}(k) for an integer k2k \ge 2 is defined as follows:

  • Let dd be the largest divisor^\dagger of kk which is not equal to kk itself. Then swap the elements ada_d and aka_k.

Suppose you perform swap(i)\texttt{swap}(i) for each i=2,3,,ni=2,3,\ldots, n in this exact order. Find the position of 11 in the resulting array. In other words, find such jj that aj=1a_j = 1 after performing these operations.

^\dagger An integer xx is a divisor of yy if there exists an integer zz such that y=xzy = x \cdot z.

Each test contains multiple test cases. The first line contains the number of test cases tt (1t1041 \le t \le 10^4). The description of the test cases follows.

The only line of each test case contains one integer nn (1n1091 \le n \le 10^9) — the length of the array aa.

For each test case, output the position of 11 in the resulting array.

Input

Each test contains multiple test cases. The first line contains the number of test cases tt (1t1041 \le t \le 10^4). The description of the test cases follows.

The only line of each test case contains one integer nn (1n1091 \le n \le 10^9) — the length of the array aa.

Output

For each test case, output the position of 11 in the resulting array.

Sample Input 1

4
1
4
5
120240229

Sample Output 1

1
4
4
67108864

Note

In the first test case, the array is [1][1] and there are no operations performed.

In the second test case, aa changes as follows:

  • Initially, aa is [1,2,3,4][1,2,3,4].
  • After performing swap(2)\texttt{swap}(2), aa changes to [2,1,3,4][\underline{2},\underline{1},3,4] (the elements being swapped are underlined).
  • After performing swap(3)\texttt{swap}(3), aa changes to [3,1,2,4][\underline{3},1,\underline{2},4].
  • After performing swap(4)\texttt{swap}(4), aa changes to [3,4,2,1][3,\underline{4},2,\underline{1}].

Finally, the element 11 lies on index 44 (that is, a4=1a_4 = 1). Thus, the answer is 44.