1. #include <stdio.h>
    int main()
    {
    long long a=1,b=1,n,i,t,F;
    scanf("%lld",&n);
    if(n<3){F=1%10007;
    }
    for(i=3;i<=n;i++)
    {
    t=a+b;F=(a+b)%10007;
    b=a;a=t;}
    printf("%lld",F);
    return 0;
    }
    

3 comments

  • @ 2024-10-8 13:40:35

    所以为什么只对四个啊

    • @ 2021-10-19 23:51:41

      学一下Markdown标记语言

      • @ 2021-10-19 23:02:33

        怎么把代码发的容易看啊,不会

        👍 1
        • 1

        Information

        ID
        38
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        8
        Tags
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