4 solutions
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0
#include <bits/stdc++.h> using namespace std; typedef long long LL; const int N = 100010; int a[N]; int b[N]; int SR(int x,int l,int r) { if(l >= r) return -1; while(l < r) { int mid = l + r + 1 >> 1; if(a[mid] <= x) { l = mid; } else r = mid - 1; } if(a[r]==x)return r; return -1; } int main () { int n ; cin >> n; for (int i = 1; i <= n; i ++) { cin >> a[i]; } int m; cin >> m; for (int i = 1; i <= m ; i ++) { cin >> b[i]; } for(int i = 1; i <= m; i ++) { cout << SR(b[i],0,n) <<' '; } return 0; }
Information
- ID
- 1231
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 7
- Tags
- # Submissions
- 342
- Accepted
- 90
- Uploaded By