2 solutions

  • 1
    @ 2022-3-15 12:31:54

    floyd算法

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n,a[55],b[55];
    	cin>>n;
    	for(int c=0;c<n;c++) cin>>a[c]>>b[c];
    	int i[55][55];
    	for(int c=0;c<n;c++){
    		for(int d=0;d<c;d++){
    			i[c][d]=i[d][c]=abs(a[c]-a[d])+abs(b[c]-b[d]);
    		}
    	}
    	for(int k=0;k<n;k++){
    		for(int c=0;c<n;c++){
    			for(int d=0;d<n;d++){
    				i[c][d]=min(i[c][d],max(i[c][k],i[k][d]));
    			}
    		}
    	}
    	int ans=0;
    	for(int c=0;c<n;c++){
    		for(int d=0;d<c;d++){
    			ans=max(ans,i[c][d]);
    		}
    	}
    	cout<<(ans+1)/2;
    }
    

    这道题似乎可以用并查集干 但是我干不来

    Information

    ID
    169
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    6
    Tags
    # Submissions
    59
    Accepted
    17
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