2 solutions
-
2
并查集加二分
#include<iostream> #include<cmath> using namespace std; int n,d[57][57],f[57]; struct A{ int x,y; }p[57]; int juli(A n1,A n2){ return abs(n1.x-n2.x)+abs(n1.y-n2.y); } int find(int x){ if(x==f[x])return x; else return f[x]=find(f[x]); } bool check(int x){ for(int i=0;i<n;i++)f[i]=i; for(int i=0;i<n;i++){ for(int j=i+1;j<n;j++){ if(d[i][j]<=x*2){ int fx=find(i),fy=find(j); if(fx!=fy)f[fx]=fy; } } } int sum=0; for(int i=0;i<n;i++){ if(f[i]==i)sum++; if(sum>=2)return false ; } return true; } int search(int l,int r){ int mid; while(l<=r){ mid=(l+r+1)>>1; if(check(mid))r=mid-1; else l=mid+1; } return l; } int main(){ cin>>n; for(int i=0;i<n;i++){ cin>>p[i].x>>p[i].y; } for(int i=0;i<n;i++){ for(int j=0;j<n;j++){ d[i][j]=juli(p[i],p[j]); d[j][i]=d[i][j]; } } int ans=search(0,500000000); cout<<ans; return 0; }
Information
- ID
- 169
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 6
- Tags
- # Submissions
- 59
- Accepted
- 17
- Uploaded By