6 solutions

  • 0
    @ 2023-10-8 23:25:02
    #include<stdio.h>
    long long w[4];
    int main(){
        //int Xa,Xb,Ya,Yb,T;//w 1,2,3,4
        int T;
        scanf("%d",&T);
        while(T>0){
            for(int i=1;i<=4;i++){
                scanf("%lld ",&w[i]);//输入
            }
                long long Q;//琪亚娜打的伤害Q
                Q=(w[4]/w[1]+1)*w[2];//n到没砍死琪亚娜先手所以多砍一下
                if(w[4]%w[1]==0) Q-=w[2];//芽衣n刀刚好砍死琪亚娜,所以把琪亚娜多砍的
                //一下伤害减去。
                
                if(Q>=w[3]){printf("YES\n");}
                else printf("NO\n");
            T--;
        }
    }   
    

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Information

ID
265
Time
1000ms
Memory
256MiB
Difficulty
8
Tags
# Submissions
1125
Accepted
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