10 solutions
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0
#include <bits/stdc++.h> using namespace std; typedef long long ll; int n,m,cnt; int a[105]; char b; int main () { cin>>n>>m; cnt=0; int k=n; while(k>0) { a[cnt]=k%m; k-=a[cnt]; k/=m; cnt++; } for(int i=cnt-1;i>=0;--i)//倒序输出 { if(a[i]>=10) { b='A'+a[i]-10; cout<<b; } else { cout<<a[i]; } } return 0; }
Information
- ID
- 288
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 4
- Tags
- # Submissions
- 121
- Accepted
- 55
- Uploaded By