Information
- ID
- 289
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 5
- Tags
- # Submissions
- 248
- Accepted
- 91
- Uploaded By
第一眼的做法,因为没卡左右括号,看看就好
#include<bits/stdc++.h>
using namespace std;
int main(){
int n=0,k=0;
char s;
while(1){
cin>>s;
if(s=='@') break;
if(s=='(') n++;
if(s==')') k++;
}
if(n==k) cout<<"YES";
else cout<<"NO";
return 0;
}
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