1 solutions
Information
- ID
- 367
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- 3
- Tags
- # Submissions
- 62
- Accepted
- 36
- Uploaded By
大家都知道判断奇偶数一直都是一个很大的问题需要考虑不下两种情况,对二取模后到底是不是等于零所以这是有一定难度的。然而在这道题本身就有难度的情况下出题人还将输出的每个字母间还空了一格让这道题难上加难!
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
if(n%2==0){
cout<<"y e s";
}else cout<<"n o";
}
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