1 solutions
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0
#include<bits/stdc++.h> using namespace std; /* 求从每个数开始连续m个数的和,打擂台求最大, 再求平均。 */ int a[110]; int main() { int n, m; cin >> n >> m; for(int i = 1; i <= n; i++){ cin >> a[i]; } //求从每个数开始连续m个数的和, //最多循环到倒数第m个数才能保证有m个数 int s; int ma = 0;//最大的和 for(int i = 1; i <= n-m+1; i++){ //求连续m个数的和 s = 0; for(int j = i; j <= i+m-1; j++){ s += a[j]; } if(s > ma) ma = s; } cout << fixed << setprecision(2) << 1.0 * ma / m; return 0; }
Information
- ID
- 505
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 9
- Tags
- # Submissions
- 10
- Accepted
- 6
- Uploaded By