2 solutions
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0
#include using namespace std; int dp[105][20005]; int main(){ int maxw, n; cin >> maxw >> n; //处理dp边界值 //0件物品时,n=0 for(int i = 0; i <= maxw; i++){ dp[0][i] = 0; } //0的重量 for(int j = 0; j <= n; j++){ dp[j][0] = 0; }
//n件物品 for(int i = 1; i <= n; i++){ int w, p; cin >> w >> p; for(int j = 1; j <= maxw; j++){ if(j < w) dp[i][j] = dp[i - 1][j]; else dp[i][j] = max(dp[i -1][j], dp[i - 1][j - w] + p); } } cout << dp[n][maxw]; return 0;
}
Information
- ID
- 620
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 8
- Tags
- # Submissions
- 113
- Accepted
- 20
- Uploaded By