5 solutions
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0
#include<math.h> int main() { double a,b,c,d,x1,x2,e; scanf("%lf %lf %lf",&a,&b,&c); d=b*b-4*a*c; if(d<0){ printf("No answer!"); }else{ if(d==0){ x1=x2=(-b)/(2*a); printf("x1=x2=%.5f",x1); }else{ e=sqrt(d); x1=(-b+e)/(2*a); x2=(-b-e)/(2*a); if(x1<x2){ printf("x1=%.5f;x2=%.5f",x1,x2); }else{ printf("x1=%.5f;x2=%.5f",x2,x1); } } }return 0; }
Information
- ID
- 6735
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 9
- Tags
- (None)
- # Submissions
- 717
- Accepted
- 73
- Uploaded By