#P1630E. Expected Components
-
ID: 6271
Type: RemoteJudge
2000ms
256MiB
Tried: 0
Accepted: 0
Difficulty: (None)
Uploaded By:
Hydro
Tags> Expected Components
No submission language available for this problem.
Description
Given a cyclic array $a$ of size $n$, where $a_i$ is the value of $a$ in the $i$-th position, there may be repeated values. Let us define that a permutation of $a$ is equal to another permutation of $a$ if and only if their values are the same for each position $i$ or we can transform them to each other by performing some cyclic rotation. Let us define for a cyclic array $b$ its number of components as the number of connected components in a graph, where the vertices are the positions of $b$ and we add an edge between each pair of adjacent positions of $b$ with equal values (note that in a cyclic array the first and last position are also adjacents).
Find the expected value of components of a permutation of $a$ if we select it equiprobably over the set of all the different permutations of $a$.
The input consists of multiple test cases. The first line contains a single integer $t$ ($1 \le t \le 10^5$) — the number of test cases. Description of the test cases follows.
The first line of each test case contains a single integer $n$ ($1 \le n \le 10^6$) — the size of the cyclic array $a$.
The second line of each test case contains $n$ integers, the $i$-th of them is the value $a_i$ ($1 \le a_i \le n$).
It is guaranteed that the sum of $n$ over all test cases does not exceed $10^6$.
It is guaranteed that the total number of different permutations of $a$ is not divisible by $M$
For each test case print a single integer — the expected value of components of a permutation of $a$ if we select it equiprobably over the set of all the different permutations of $a$ modulo $998\,244\,353$.
Formally, let $M = 998\,244\,353$. It can be shown that the answer can be expressed as an irreducible fraction $\frac{p}{q}$, where $p$ and $q$ are integers and $q \not \equiv 0 \pmod{M}$. Output the integer equal to $p \cdot q^{-1} \bmod M$. In other words, output such an integer $x$ that $0 \le x < M$ and $x \cdot q \equiv p \pmod{M}$.
Input
The input consists of multiple test cases. The first line contains a single integer $t$ ($1 \le t \le 10^5$) — the number of test cases. Description of the test cases follows.
The first line of each test case contains a single integer $n$ ($1 \le n \le 10^6$) — the size of the cyclic array $a$.
The second line of each test case contains $n$ integers, the $i$-th of them is the value $a_i$ ($1 \le a_i \le n$).
It is guaranteed that the sum of $n$ over all test cases does not exceed $10^6$.
It is guaranteed that the total number of different permutations of $a$ is not divisible by $M$
Output
For each test case print a single integer — the expected value of components of a permutation of $a$ if we select it equiprobably over the set of all the different permutations of $a$ modulo $998\,244\,353$.
Formally, let $M = 998\,244\,353$. It can be shown that the answer can be expressed as an irreducible fraction $\frac{p}{q}$, where $p$ and $q$ are integers and $q \not \equiv 0 \pmod{M}$. Output the integer equal to $p \cdot q^{-1} \bmod M$. In other words, output such an integer $x$ that $0 \le x < M$ and $x \cdot q \equiv p \pmod{M}$.
Samples
5
4
1 1 1 1
4
1 1 2 1
4
1 2 1 2
5
4 3 2 5 1
12
1 3 2 3 2 1 3 3 1 3 3 2
1
2
3
5
358642921
Note
In the first test case there is only $1$ different permutation of $a$:
- $[1, 1, 1, 1]$ has $1$ component.
- Therefore the expected value of components is $\frac{1}{1} = 1$
In the second test case there are $4$ ways to permute the cyclic array $a$, but there is only $1$ different permutation of $a$:
- $[1, 1, 1, 2]$, $[1, 1, 2, 1]$, $[1, 2, 1, 1]$ and $[2, 1, 1, 1]$ are the same permutation and have $2$ components.
- Therefore the expected value of components is $\frac{2}{1} = 2$
In the third test case there are $6$ ways to permute the cyclic array $a$, but there are only $2$ different permutations of $a$:
- $[1, 1, 2, 2]$, $[2, 1, 1, 2]$, $[2, 2, 1, 1]$ and $[1, 2, 2, 1]$ are the same permutation and have $2$ components.
- $[1, 2, 1, 2]$ and $[2, 1, 2, 1]$ are the same permutation and have $4$ components.
- Therefore the expected value of components is $\frac{2+4}{2} = \frac{6}{2} = 3$
In the fourth test case there are $120$ ways to permute the cyclic array $a$, but there are only $24$ different permutations of $a$:
- Any permutation of $a$ has $5$ components.
- Therefore the expected value of components is $\frac{24\cdot 5}{24} = \frac{120}{24} = 5$