1 solutions
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0
#include <iostream> #include <bits/stdc++.h> using namespace std; int jiecheng(int x){ int sum = 1; for(int i = 1 ;i <= x ;i++){ sum *= i; } return (sum); } int main() { int N; cin >> N; int sum = 0; for(int i = 1 ;i <= N ;i++){ sum += jiecheng(i); } cout << sum; return 0; }
- 1
Information
- ID
- 351
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- 2
- Tags
- # Submissions
- 109
- Accepted
- 65
- Uploaded By