1 solutions
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0
#include<bits/stdc++.h> using namespace std; int main() { //num计数满足条件的数的个数 int k, sub1, sub2, sub3, num = 0; cin >> k; //遍历10000到30000之间的五位数 for(int i = 10000; i <= 30000; i++){ sub1 = i/100; sub2 = i/10%1000; sub3 = i%1000; if(sub1%k == 0 && sub2%k == 0 && sub3%k == 0){ cout << i << endl; num++; } } //如果无解,则输出“no"; if(num == 0){ cout << "No"; } return 0; }
- 1
Information
- ID
- 794
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- 10
- Tags
- # Submissions
- 2
- Accepted
- 2
- Uploaded By