1 solutions
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0
#include<bits/stdc++.h> using namespace std; int main() { int a[110],n,mi; cin >> n; for(int i = 0; i < n; i++){ cin >> a[i]; } mi = a[0];//查找最小的数 for(int i = 1; i < n; i++){ if(a[i] < mi){ mi = a[i]; } } //输出除了最小数以外的数 for(int i = 0; i < n; i++){ if(a[i] != mi){ cout << a[i] << " "; } } return 0; }
- 1
Information
- ID
- 553
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- 10
- Tags
- # Submissions
- 4
- Accepted
- 4
- Uploaded By