1 solutions

  • 0
    @ 2023-1-17 22:12:10
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int i,j,x,y;
    	//循环男人可能的人数
    	for(i = 0; i <= 50 / 3; i++){
    		//剩余的钱
    		x = 50 - i * 3;
    		//循环女人可能的人数
    		for(j = 0; j <= x / 2; j++){
    			y = x - j * 2;
    			//剩余的y元,分配给小孩,要求总人数为30
    			if(i+j+y == 30){
    				cout << i << " " << j << " " << y << endl;
    			} 
    		} 
    	} 
    	return 0;
    }
    
    
    • 1

    Information

    ID
    590
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    10
    Tags
    # Submissions
    2
    Accepted
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