1 solutions
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0
#include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> #include<cstring> #include<algorithm> #include<vector> #include<string> #include<map> #include <climits> using namespace std; const int N = 1e5 + 5; bool isprime[N]; int prime[100005]; int c; void oula(int a, int b)//欧拉素数筛筛出素数存到数组里面去 { a = 2; for (int i = a;i <= b; i++) { if (!isprime[i]) prime[++c] = i; for (int j = 1; j <= c && i * prime[j] <= b; j++) { isprime[i * prime[j]] = true; if (i % prime[j] == 0) break; } } } int main(void) { int a, b; cin >> a >> b; oula(a, b); for(int i=a;i<=b;i++) { if (!isprime[i]) cout << i << "=" << i<<endl; else { cout << i << "="; int k = i; for (int t = 1; t <= c; t++) { if (k % prime[t] == 0) { if (k / prime[t] != 1) cout << prime[t] << "*"; else { cout << prime[t]; cout << endl; } k /= prime[t]; t--;//4=2*2的情况 } } } } return 0; }
- 1
Information
- ID
- 1174
- Time
- 1000ms
- Memory
- 512MiB
- Difficulty
- 7
- Tags
- # Submissions
- 17
- Accepted
- 9
- Uploaded By