1 solutions
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0
#include<bits/stdc++.h> using namespace std; int n,l,r,m,k; const int N=1e8+5; int f[N]; int find(int g){ l=1,r=n; while(l<=r){ int mid=(l+r)/2; if(f[mid]>=g){ r=mid-1; } else{ l=mid+1; } } if(f[l]>=g){ return l; } else{ return -1; } } int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>f[i]; } cin>>m; while(m--){ cin>>k; cout<<find(k)<<" "; } return 0; }
- 1
Information
- ID
- 1232
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 3
- Tags
- # Submissions
- 79
- Accepted
- 43
- Uploaded By