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1030 压力测试赛B题题解
题目回顾
Krik晚上失眠，躺着很无聊，于是突发奇想道阳台上去看星星。不失所望，那夜繁星当空、星河奔流。Kirk越看越精神，在繁星中发现了一个又一个的数字，刚学编程不久的Kirk想到，电脑上也有星星，何不操作一波呢！ 经过一番痛苦的敲键盘事件之后，终于Kirk电脑屏幕上出现了下图十个数字的星星表达式：
（本来想给文本的，但是文本太丑了） 为了让大家体会一下Kirk痛苦的敲代码事件，所以Kirk给你两个整数A和B，你的任务是计算A+B的结果并且使用星星表达式输出
题目分析
从题中所给出的信息，我们可以得出：
- 两个数字相加会得到一个结果，并把结果转化为特殊表达形式输出。
- 特殊表达式如图所示，由于CMD的特性，只能一行输出完再输出下一行，所以我们要对每个数做一个拆解，把每一行特定输出。
- 特别要注意的是，测试样例中给出，两个数字之间有一个空格，第二个数字后无空格。
可行代码
这里给大家贴三份代码 (注：不建议直接CV过去解决问题，打表考的是细心，自己实操一下是最好的 /笔芯) Kirk的垃圾代码（强烈建议看看后面两篇比较好的写法，同时这也是几种不同思路，不说了Kirk思路最差）
#include <stdio.h> void cout0(int line) { if (line == 1) printf("***"); else if (line == 2) printf("* *"); else if (line == 3) printf("* *"); else if (line == 4) printf("* *"); else if (line == 5) printf("***"); } void cout1(int line) { if (line == 1) printf(" * "); else if (line == 2) printf(" * "); else if (line == 3) printf(" * "); else if (line == 4) printf(" * "); else if (line == 5) printf(" * "); } void cout2(int line) { if (line == 1) printf("***"); else if (line == 2) printf(" *"); else if (line == 3) printf("***"); else if (line == 4) printf("* "); else if (line == 5) printf("***"); } void cout3(int line) { if (line == 1) printf("***"); else if (line == 2) printf(" *"); else if (line == 3) printf("***"); else if (line == 4) printf(" *"); else if (line == 5) printf("***"); } void cout4(int line) { if (line == 1) printf("* *"); else if (line == 2) printf("* *"); else if (line == 3) printf("***"); else if (line == 4) printf(" *"); else if (line == 5) printf(" *"); } void cout5(int line) { if (line == 1) printf("***"); else if (line == 2) printf("* "); else if (line == 3) printf("***"); else if (line == 4) printf(" *"); else if (line == 5) printf("***"); } void cout6(int line) { if (line == 1) printf("***"); else if (line == 2) printf("* "); else if (line == 3) printf("***"); else if (line == 4) printf("* *"); else if (line == 5) printf("***"); } void cout7(int line) { if (line == 1) printf("***"); else if (line == 2) printf(" *"); else if (line == 3) printf(" *"); else if (line == 4) printf(" *"); else if (line == 5) printf(" *"); } void cout8(int line) { if (line == 1) printf("***"); else if (line == 2) printf("* *"); else if (line == 3) printf("***"); else if (line == 4) printf("* *"); else if (line == 5) printf("***"); } void cout9(int line) { if (line == 1) printf("***"); else if (line == 2) printf("* *"); else if (line == 3) printf("***"); else if (line == 4) printf(" *"); else if (line == 5) printf("***"); } int main() { int A, B; scanf("%d%d", &A, &B); int res = A + B; // 数据保证 10 <= A + B < 100 int num1 = res / 10; int num2 = res % 10; for (int j = 1; j <= 6; j++) { if (num1 == 0) cout0(j); else if (num1 == 1) cout1(j); else if (num1 == 2) cout2(j); else if (num1 == 3) cout3(j); else if (num1 == 4) cout4(j); else if (num1 == 5) cout5(j); else if (num1 == 6) cout6(j); else if (num1 == 7) cout7(j); else if (num1 == 8) cout8(j); else if (num1 == 9) cout9(j); putchar(' '); if (num2 == 0) cout0(j); else if (num2 == 1) cout1(j); else if (num2 == 2) cout2(j); else if (num2 == 3) cout3(j); else if (num2 == 4) cout4(j); else if (num2 == 5) cout5(j); else if (num2 == 6) cout6(j); else if (num2 == 7) cout7(j); else if (num2 == 8) cout8(j); else if (num2 == 9) cout9(j); putchar('\n'); } return 0; }大佬代码一（膜拜）
#include<iostream> using namespace std; string x[15][10]; int ans[105],cou; int main(){ ios::sync_with_stdio(false); x[0][0]="***"; x[0][1]="* *"; x[0][2]="* *"; x[0][3]="* *"; x[0][4]="***"; x[1][0]=" * "; x[1][1]=" * "; x[1][2]=" * "; x[1][3]=" * "; x[1][4]=" * "; x[2][0]="***"; x[2][1]=" *"; x[2][2]="***"; x[2][3]="* "; x[2][4]="***"; x[3][0]="***"; x[3][1]=" *"; x[3][2]="***"; x[3][3]=" *"; x[3][4]="***"; x[4][0]="* *"; x[4][1]="* *"; x[4][2]="***"; x[4][3]=" *"; x[4][4]=" *"; x[5][0]="***"; x[5][1]="* "; x[5][2]="***"; x[5][3]=" *"; x[5][4]="***"; x[6][0]="***"; x[6][1]="* "; x[6][2]="***"; x[6][3]="* *"; x[6][4]="***"; x[7][0]="***"; x[7][1]=" *"; x[7][2]=" *"; x[7][3]=" *"; x[7][4]=" *"; x[8][0]="***"; x[8][1]="* *"; x[8][2]="***"; x[8][3]="* *"; x[8][4]="***"; x[9][0]="***"; x[9][1]="* *"; x[9][2]="***"; x[9][3]=" *"; x[9][4]="***"; int a,b; cin>>a>>b; int xx=a+b,y=0,yy; while(xx){ ans[cou++]=xx%10; xx/=10; } for(int i=0;i<5;i++){ yy=y; for(int j=cou-1;j>=0;j--){ cout<<x[ans[j]][i]; if(j)cout<<' '; } cout<<endl; } return 0; } #include<iostream> using namespace std; char n0[6][6]={"***","* *","* *","* *","***"},n1[6][6]={" * "," * "," * "," * "," * "}; char n2[6][6]={"***"," *","***","* ","***"},n3[6][6]={"***"," *","***"," *","***"}; char n4[6][6]={"* *","* *","***"," *"," *"},n5[6][6]={"***","* ","***"," *","***"}; char n6[6][6]={"***","* ","***","* *","***"},n7[6][6]={"***"," *"," *"," *"," *"}; char n8[6][6]={"***","* *","***","* *","***"},n9[6][6]={"***","* *","***"," *","***"}; int main() { int a,b; cin>>a>>b; int c=a+b; char s[3]; s[1]=c/10; s[2]=c%10; int flag=0; for(int p=0;p<5;p++) { for(int j=1;j<3;j++) { if(s[j]==1)cout<<n1[p]; if(s[j]==2)cout<<n2[p]; if(s[j]==3)cout<<n3[p]; if(s[j]==4)cout<<n4[p]; if(s[j]==5)cout<<n5[p]; if(s[j]==6)cout<<n6[p]; if(s[j]==7)cout<<n7[p]; if(s[j]==8)cout<<n8[p]; if(s[j]==9)cout<<n9[p]; if(s[j]==0)cout<<n0[p]; if(j==1)cout<<" "; } cout<<"\n"; } return 0; }大佬代码二（继续膜拜）
#include<iostream> using namespace std; char n0[6][6]={"***","* *","* *","* *","***"},n1[6][6]={" * "," * "," * "," * "," * "}; char n2[6][6]={"***"," *","***","* ","***"},n3[6][6]={"***"," *","***"," *","***"}; char n4[6][6]={"* *","* *","***"," *"," *"},n5[6][6]={"***","* ","***"," *","***"}; char n6[6][6]={"***","* ","***","* *","***"},n7[6][6]={"***"," *"," *"," *"," *"}; char n8[6][6]={"***","* *","***","* *","***"},n9[6][6]={"***","* *","***"," *","***"}; int main() { int a,b; cin>>a>>b; int c=a+b; char s[3]; s[1]=c/10; s[2]=c%10; int flag=0; for(int p=0;p<5;p++) { for(int j=1;j<3;j++) { if(s[j]==1)cout<<n1[p]; if(s[j]==2)cout<<n2[p]; if(s[j]==3)cout<<n3[p]; if(s[j]==4)cout<<n4[p]; if(s[j]==5)cout<<n5[p]; if(s[j]==6)cout<<n6[p]; if(s[j]==7)cout<<n7[p]; if(s[j]==8)cout<<n8[p]; if(s[j]==9)cout<<n9[p]; if(s[j]==0)cout<<n0[p]; if(j==1)cout<<" "; } cout<<"\n"; } return 0; }END 预祝学习愉快 /狗头
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#include
using namespace std;
string number[10][5] = {
{""," "," "," ",""},//0
{" * "," * "," * "," * "," * "},//1
{""," ",""," ","***"},//2
{""," ",""," ","*"},//3
{"* "," ","**"," *"," *"},//4
{""," ",""," ","*"},//5
{""," ",""," ","**"},//6
{"***"," *"," *"," *"," *"},//7
{""," ","","* ","**"},//8
{""," ",""," ","**"}//9
};
int main(){
int a,b,sum[2]; cin>>a>>b; int S = a+b;//个位 sum[0] = S/10%10;//十位 for(int i = 0;i<5;i++){//行行处理，共五行，一行两个操作，嵌套关系 for(int j = 0;j<2;j++){ cout<<number[sum[j]][i]; if(j==0)cout<<" "; else cout<<endl; } } return 0;}
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打表并合理运用下标
#include <bits/stdc++.h> using namespace std; #define DBG(x) cout << #x << "=" << x << endl char g[10][5][5] = { { // 0 "***", "* *", "* *", "* *", "***", }, { // 1 " * ", " * ", " * ", " * ", " * ", }, { // 2 "***", " *", "***", "* ", "***", }, { // 3 "***", " *", "***", " *", "***", }, { // 4 "* *", "* *", "***", " *", " *", }, { // 5 "***", "* ", "***", " *", "***", }, { // 6 "***", "* ", "***", "* *", "***", }, { // 7 "***", " *", " *", " *", " *", }, { // 8 "***", "* *", "***", "* *", "***", }, { // 9 "***", "* *", "***", " *", "***", } }; int nums[3] = {0, 0, 0}; void solve() { int a, b; cin >> a >> b; int n = a + b; int t = 2; while (n) { nums[t--] = n % 10; n /= 10; } for (int r = 0; r < 5; r++) { for (int i = 0; i <= 2; i++) { if (i == 0 && nums[0] == 0) continue; if (i == 1 && nums[0] == 0 && nums[1] == 0) continue; int num = nums[i]; cout << g[num][r] << (i == 2 ? "" : " "); } cout << endl; } } int main() { solve(); return 0; } -
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import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int end = sc.nextInt() + sc.nextInt(); int n1, n2; n1 = end / 10; n2 = end % 10; String[][] stars = stars(n1, n2); printString(stars); } static String[][] copyT(String[][] a, String[][] b) { String[][] c = new String[5][7]; for (int i = 0; i < 5; i++) { for (int j = 0; j < 3; j++) { c[i][j] = a[i][j]; } } for (int i = 0; i < 5; i++) { c[i][3] = " "; } for (int i = 0; i < 5; i++) { for (int j = 4; j < 7; j++) { c[i][j] = b[i][j - 4]; } } return c; } static String[][] stars(int n1, int n2) { String[][] a = drawStars(n1); String[][] b = drawStars(n2); return copyT(a, b); } static String[][] drawStars(int n) { String[][] a = new String[5][3]; reset(a); if (n == 0) { s0(a); } else if (n == 1) { s1(a); } else if (n == 2) { s2(a); } else if (n == 3) { s3(a); } else if (n == 4) { s4(a); } else if (n == 5) { s5(a); } else if (n == 6) { s6(a); } else if (n == 7) { s7(a); } else if (n == 8) { s8(a); } else if (n == 9) { s9(a); } return a; } static void reset(String[][] a) { for (int i = 0; i < 5; i++) { for (int j = 0; j < 3; j++) { a[i][j] = "*"; } } } static void s9(String[][] a) { s8(a); a[3][0] = " "; } static void s8(String[][] a) { s0(a); a[2][1] = "*"; } static void s7(String[][] a) { for (int i = 1; i < 5; i++) { a[i][0] = " "; a[i][1] = " "; } } static void s6(String[][] a) { s5(a); a[3][0] = "*"; } static void s5(String[][] a) { s3(a); a[1][0] = "*"; a[1][2] = " "; } static void s4(String[][] a) { s9(a); a[0][1] = " "; a[4][1] = " "; a[4][0] = " "; } static void s3(String[][] a) { s2(a); a[3][2] = "*"; a[3][0] = " "; } static void s2(String[][] a) { s0(a); a[2][1] = "*"; a[1][0] = " "; a[3][2] = " "; } static void s1(String[][] a) { for (int i = 0; i < 5; i++) { a[i][0] = " "; a[i][2] = " "; } } static void s0(String[][] a) { a[1][1] = " "; a[2][1] = " "; a[3][1] = " "; } static void printString(String[][] a) { for (int i = 0; i < 5; i++) { for (int j = 0; j < 7; j++) { System.out.print(a[i][j]); } if (i != 4) { System.out.println(); } } } }
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