7 solutions
- 1
Information
- ID
- 34
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 8
- Tags
- # Submissions
- 3002
- Accepted
- 432
- Uploaded By
#include <bits/stdc++.h>
using namespace std;
int main()
{
long long n;
cin>>n;
cout<<(n+1)*n/2;
return 0;
}
#include <stdio.h> int main() { int result, x, y;
scanf_s("%d",&x);
for (result = 0, y = 1; y <= x; y++)
{
result = result + y;
};
printf("%d",result);
return 0;
}
这题要注意int的范围可能不够🤔
#include <iostream>
using namespace std;
int main()
{
long long n = 0;
long long sum = 0;
cin >> n;
for(int i = 1; i <= n; i++)
sum += i;
cout << sum << endl;
return 0;
}
while True:
try:
n = input()
sum = 0
for i in range(n+1):
sum += i
print(sum)
except:
break
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