1 solutions
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1
#include<iostream> using namespace std; const int N=100010; int p[N]; int find(int x) { if(p[x]!=x) p[x]=find(p[x]); return p[x]; } void merge(int x,int y) { int xx=find(x); int yy=find(y); if(xx!=yy) p[xx]=yy; } int main(){ int n,m; while(cin>>n>>m) { for(int i=1;i<=n;i++) p[i]=i; for(int i=1;i<=m;i++) { int x,y; cin>>x>>y; merge(x,y); } int sum=0; for(int i=1;i<=n;i++) if(p[i]==i) sum++; cout<<sum-1<<endl; } return 0; }
- 1
Information
- ID
- 273
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 6
- Tags
- # Submissions
- 28
- Accepted
- 18
- Uploaded By