4 solutions

  • 0
    @ 2025-11-2 18:31:10

    #include<stdio.h>

    int main(){

    int m=0,k=0,c=0,i=0;

    scanf("%d %d",&m,&k);

    while(m>0){

    c=m%10;

    m/=10;if(c==k){

    i++;

    }}

    if(m%19==0&&i>1&&i<5){

    printf("YES");

    }else{printf("NO");

    }

    return 0;

    }

    • 0
      @ 2024-10-7 18:36:00

      #include <stdio.h> int main() { int m,k,i; int cnt=0; int digit; scanf("%d %d",&m,&k); for(i=0;i<=k;i++){ digit=m%10; m=m/10; if(digit3){ cnt++; } } if(cntk){ printf("YES"); }else{ printf("NO"); } return 0; }

      • 0
        @ 2023-10-25 16:05:10
        #include <stdio.h>
        #include<math.h>
        #pragma warning(disable:4996) 
        int main()
        {
            int m, k, temp = 0;
           
            scanf("%d%d", &m, &k);
            if (m % 19 == 0)
            {
                while (m)
                {
                    if (m % 10 == 3) temp ++ ;
                    m /= 10;
                }
            }
            if (temp == k)
            {
                printf("YES");
            }
            else
            {
                printf("NO");
            }
         
            return 0;
        }
        
        • 0
          @ 2023-10-10 20:25:27

          #include <stdio.h> int main() { long long m; int k=0; long long F; scanf("%lld",&m);

          F=m;
          do{
          	if((F%10)==3){
          		k++;
          	}
          	F/=10;
          } while(F!=0);
          
          if(m%19==0){
          	if(k==3){
          		printf("YES");
          	}
          }else {
          	printf("NO");
          }
          return 0;
          

          }

          • 1

          Information

          ID
          6756
          Time
          1000ms
          Memory
          128MiB
          Difficulty
          4
          Tags
          (None)
          # Submissions
          169
          Accepted
          80
          Uploaded By