1 solutions
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0
#include <stdio.h> int main() { int n,m,i,t; int sum=0; scanf("%d %d",&m,&n); int a[m][n]; for(i=0;i<m;i++){ for(t=0;t<n;t++){ scanf("%d ",&a[i][t]); } } for(i=0;i<m;i++){ sum=sum+a[i][0]+a[i][n-1]; } for(i=1;i<n-1;i++){ sum=sum+a[0][i]+a[m-1][i]; } printf("%d",sum); return 0; }
- 1
Information
- ID
- 6779
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 2
- Tags
- (None)
- # Submissions
- 47
- Accepted
- 29
- Uploaded By