1 solutions
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  0
#include <stdio.h> int main() { int n,m,i,t; int sum=0; scanf("%d %d",&m,&n); int a[m][n]; for(i=0;i<m;i++){ for(t=0;t<n;t++){ scanf("%d ",&a[i][t]); } } for(i=0;i<m;i++){ sum=sum+a[i][0]+a[i][n-1]; } for(i=1;i<n-1;i++){ sum=sum+a[0][i]+a[m-1][i]; } printf("%d",sum); return 0; }
 
- 1
 
Information
- ID
 - 6779
 - Time
 - 1000ms
 - Memory
 - 128MiB
 - Difficulty
 - 3
 - Tags
 - (None)
 - # Submissions
 - 67
 - Accepted
 - 36
 - Uploaded By