1 solutions

  • 0
    @ 2024-10-25 18:55:03

    #include <stdio.h> int main() { int m,n,t,i; double sum=0; scanf("%d %d",&m,&n); int a[m][n]; int b[m][n]; for(t=0;t<m;t++){ for(i=0;i<n;i++){ scanf("%d",&a[t][i]);
    } } for(t=0;t<m;t++){ for(i=0;i<n;i++){ scanf("%d",&b[t][i]);
    } } for(t=0;t<m;t++){ for(i=0;i<n;i++){ if(b[t][i]==a[t][i]){ sum++; } } } double k; k=(sum/(m*n))*100; printf("%.2lf",k); return 0; }

    • 1

    Information

    ID
    6781
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    7
    Tags
    (None)
    # Submissions
    126
    Accepted
    33
    Uploaded By