Information
- ID
- 6482
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- # Submissions
- 104
- Accepted
- 49
- Uploaded By
#include<iostream>
#include<iomanip>
using namespace std;
int main(){
int n, x, cnt1 = 0, cnt2 = 0; //总人数,分数,及格人数,优秀人数
float ratio1, ratio2; //及格率, 优秀率
cin >> n;
for(int i = 1; i <= n; i++){
cin >> x;
if(x >= 60) cnt1++;
if(x >= 85) cnt2++;
}
ratio1 = 1.0 * cnt1/n * 100; //因为cnt1 和 n 都为整数,所以乘以1.0转成浮点数
ratio2 = 1.0 * cnt2/n * 100;
cout << setprecision(0) << fixed << ratio1 << "%\n"<<ratio2 << "%\n" << endl; //四舍五入,保留整数
return 0;
}
//stl:int round(double x) ----->四舍五入函数
#include<bits/stdc++.h>
using namespace std;
int n,a,b,x;
int main(){
//freopen("t.in","r",stdin);
//freopen("t.out","w",stdout);
cin>>n;
int tmp=n;
while(tmp--){
cin>>x;
if(x>=60)b++;
if(x>=85)a++;
}
double ans1=(double)b/n*100;
double ans2=(double)a/n*100;
cout<<round(ans1)<<"%"<<endl;
cout<<round(ans2)<<"%";
return 0;
}
By signing up a 追梦算法网 universal account, you can submit code and join discussions in all online judging services provided by us.